![]() ![]() The NodeBox has a document window which consists of the Viewer Pane which shows the composition the user is working on, the Parameters Pane which allows users to adjust the parameter values of a node, the Network Pane which shows all nodes and their connections and the Source Pane which contains the source code of the currently selected node. NodeBox has a large set of external libraries such as the SVG library for importing SVG paths, the Bezier editor for drawing right inside of the application, and Core Image for doing Photoshop-like image manipulations like layers with blending modes, color changes and filters using the OS X Core Image library, which is hardware accelerated. NodeBox also supports images and text with line wrapping and users can specify fill and stroke colors using RGB, HSB or CMYK, all with alpha transparency. NodeBox not only supports simple forms such as rectangles, ovals, stars, and arrows, but also Bezier paths in general. Nodebox lets users code in Python instead of Java where Nodebox comes with a lot of built-in tools such as flocking, particle systems and graphs and an easy access to all the tools available in Python. Create a range node and send count1 to End. We will use this number to figure out what degree each segment needs and to create a range to multiply it to this segmentsize. NodeBox offers features such as Python programming code, export as a PDF or a QuickTime movie, create static, animated or interactive compositions using simple primitives such as rectangles and ovals, import images and vector files from Photoshop and Illustrator, play around with text paths, supports Core Image, create layered images using transformations, blend modes, alpha masks and filters and all hardware-accelerated. Create a count node and connect importcsv1 to it. If you tell me a bit more about your project I may be able to help.NodeBox is an easy-to-use, efficient, and fast node-based software application which makes it easy to do data visualizations, generative design and complex production challenges. I have done this before in NodeBox as well. This problem is similar to the task of creating a treemap, a visualization of a hierarchical structure as boxes within boxes that fill a rectangular space. More complex patterns could also be handled if you have can choose your possible sizes carefully. In one project I did, there were three possible sizes of square box, 4x4, 2x2, and 1x1, so that I could always fill the column width exactly. One thing you can do is sort your list by width so that all the widest boxes are dealt with first. date), or are you simply filling the space any way you can? Does it matter what order the boxes are stacked?ĭepending on how you answer these questions, there may be some way of calculating an acceptable arrangement ahead of time. What are the constraints on your boxes? What is the minimum and maximum height and width? Are they integer values or completely unpredictable? Are they arranged in different columns according to some other factor (e.g. There is usually a way of doing almost anything if you think about it in the right way. I have created stacks of multi-sized boxes in NodeBox before. I attach a picture of two arrangements to show, what I want to accomplish. So I think I have to work with different lists, but as I have to select objects in dependence of previous objects I can't find a way to go back in a list or save the current version of the arrangement before positioning the next object. So for every "A" for example there are four different versions The first objects is random and the following object has to fill the "line" if hoizontal space is left and at the same time look for the vertical length of the previous object. Each of the objects represents one version of a letter. ![]() What I finally want to do is to arrange (in dependency of written letters) 4 different objects of two different widths and hights in columns so that they finally fill a column. So my question was wrong.Īctually I have to consider not only the position of one item in a list, but also for each previous item and their properties. I tried something like your example but then recognized, that my problem is far more complicated then I wrote in my question. Thank you very much Frederik for your fast answer. ![]()
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